Yintoni idiagonal ityhubhu, nendlela yokufumana ngayo

Yintoni ityhubhu, yaye oko anako oxwesileyo

Cube (Ipolihedron rhoqo okanye hexahedron) oyintsobi-ntathu, ubuso nganye - yinto isikwere, apho, njengokuba sisazi, macala onke bayalingana. cube oxwesileyo na icandelo ugqithayo kuwo embindini mzobo senginginya nodibaniso iincopho macala. Xa hexahedron njengelungelo idiagonal-4, yaye bonke iya kulingana. Kubalulekile ukuba edidekile idiagonal mzobo ngokwayo nge ubuso bayo oxwesileyo okanye isikwere, edulusele kwi kwisiseko sayo. Oxwesileyo we tyhubhu udlula embindini ubuso kwaye ifaka eziphezulu icala isikwere.

Formula ezinokuthi ukufumana idiagonal cube

Ipolihedron oxwesileyo rhoqo lungafumaneka ifomula elula kakhulu ukuba ufuna ukuzikhumbula. D = a√3, apho D imela idiagonal le tyhubhu, yaye - le buthelezi. Nanku umzekelo ingxaki, apho kuyimfuneko ukufumana idiagonal, ukuba uyazi ukuba ilingane ubude ngohlangothi-2 cm. Yinto D elula = 2√3, musa nokuba kufuneka siqwalasele nto. Xa umzekelo wesibini, makhe ngohlangothi cube 'ulingana √3 cm, ngoko bafumane D = √3√3 = √9 = 3. Impendulo: D ilingana no-3 cm.

Formula ezinokuthi ukufumana idiagonal ityhubhu Name

Diago facets Nahl ingafunyanwa nayo yi ifomula. Idayagonali, leyo kulala ebusweni amaqhosha nje 12, kwaye bonke bayalingana. Ngoku khumbula d = a√2, apho d - ke idiagonal yembutho, yaye - kukwayinto entle kumngcipheko ityhubhu okanye icala isikwere. Ukuze uqonde apho le fomyula ilula kakhulu. Ngapha koko, emacaleni aso omabini isikwere kunye nefomu nemigca a unxantathu lasekunene-engile egqithe. Le trio udlala indima yokuba hypotenuse oxwesileyo kunye icala kwisikwere - yeyona imilenze ukuba ubude efanayo. Masikhumbule ukuba theorem kaPythagoras, nabo bonke kwaoko niya kuwela ndawo. Ngoku ingxaki: kumngcipheko hexahedron ilingana √8 kubona, kuyimfuneko ukufumana idiagonal ubuso bayo. Lifakwa ifomula, kwaye bafumane singathanda = √8 √2 = √16 = 4. Impendulo: I idiagonal le tyhubhu 4 cm.

Ukuba siyazi ubuso cube oxwesileyo

Ngokutsho kwingxelo ingxaki, sinikwa kuphela ubuso idiagonal emacala rhoqo, nto leyo ilingana, nithi, √2 cm, yaye sifuna ukufumana idiagonal a ityhubhu. Ifomula ukusombulula le ngxaki ngakumbi kancinane xaka wangaphambili. Ukuba siyazi d, siya kufumana ngohlangothi tyhubhu, ngokusekelwe yesibini formula d = a√2 yethu. Sifumana = d / √2 = √2 / √2 = 1cm (lo izakhono zethu). Ukuba siyazi eli xabiso, ngoko ufumane cube oxwesileyo Akukho nzima: D = 1√3 = √3. Nantso indlela osombulule umsebenzi wethu leyo.

Ukuba indawo eyaziwa surface

Le algorithm ilandelayo isekelwe ukufumana izisombululo kwikonw ngekona kwi kwindawo kobuso ityhubhu. Zicinge ukuba ilingana no-72 cm ^2. Ukuze ufumane ekuqaleni kwingingqi ubuso, yaye abangama-6, 72 kufuneka umahlule ngo 6, sinokuyifumana 12 cm ^2. Le yenye ummandla ebusweni. Ukuze ufumane ngohlangothi emacala rhoqo, kuyimfuneko ukuba ukukhumbula ifomula S = ^2, ngoko a = √S. Tshintsha kwaye bafumane = √12 (cube edge). Ukuba siyazi eli xabiso, kwaye kunzima ukufumana D oxwesileyo = a√3 = √12 √3 = √36 = 6. Impendulo: I idiagonal enamacala ilingana 6 cm ^2.

Ukuba eyaziwa ubude beskrini cube

Kukho iimeko apho ingxaki unikwa kuphela ubude zonke kungqameko ibokisi. Ngoko kuyimfuneko ukuba kuwabela 12 Nantso inani amaqela ezimacala rhoqo. Umzekelo, ukuba udibaniso lwamaxabiso wonke ezinemiphetho ilingana no-40, elinye icala iya kulingana 40/12 = 3,333. Sibeka ifomula yethu yokuqala uze ufumane impendulo!