Indlela yokufumana kummandla irhombus?

Indlela yokufumana kummandla irhombus? Ukunika impendulo, kufuneka kuqala siqonde ukuba yintoni sicinga nekalikedo.

Okokuqala, a quadrangle. Okwesibini, inamacala amane alinganayo. Okwesithathu, idayagonali ayo nkqo abakwindawo ekudibaneni. Okwesine, kuhlangana indawo oxwesileyo zahlulwe alinganayo. Okwesihlanu, isabelo esifanayo kwiimbombo idiagonal le irhombus ibe ngamaqela amabini alinganayo. Yesithandathu, sum of engile ezimbini ezikufutshane icala elinye, yenza le angle unwrapped, ngamanye 180 degrees. Ukuba uthi nje, nekalikedo - ngesikwere kophahla.

Ukuba uthatha isikwere ogama amacala zibambene evumayo ngokulula kume kwi engile ezimbini esahlukileyo, isikwere uya kulahlekelwa squareness yayo kwaye ijike ibe nekalikedo. Ngoko ke, lo diamond kunye engile ekunene - oku isikwere wokwenene.

Owokuqala ukwazisa isigama Hero diamond Pappus waseAlexandria, imathematika zamaGrike. Igama elithi "diamond" of the Greek anokuguqulelwa ngokuthi "igubu".

Ukuze ufumane indawo yiRHOMBUS, kubalulekile ukuqwalasela ukuba diamond - yinto parallelogram. Kwaye indawo ye parallelogram inokufunyanwa phinda phakathi isiseko, oko kukuthi ulwalathiso nokuphakama.

Ukungqina oku, kufuneka kusukela phezulu saso ezimbombeni zaso esisemantla perpendiculars irhombus. Umzekelo, anikwe QWER kwedayimani. Ukususela eziphezulu saso ezimbombeni zaso aphezulu Q kunye perpendiculars W QT kunye WY. Kwaye nkqo QT iwela ngakwicala RE, kwaye nkqo WY kwi phambili nganeno.

Ngaloo ndlela, amatsha wajika QWYT Ikwadrilatherali enamacala parallel kunye engile tye, leyo, olusekelwe phezu zingasentla, kusenokwenzeka ukuba igama ngenkalipho yoxande.

Le ndawo yalo xande lilwandisela ecaleni nokuphakama. Ngoku kufuneka angqine ukuba kummandla kwindawo yoxande kubangele lihambisana imeko lithile nekalikedo.

Ukuqwalasela efunyenwe kusakhiwa oonxantathu ezongezelelweyo QYR kunye Wet, singatsho ukuba kwi emlenzeni kunye hypotenuse. Emva zonke imilenze triangles kuqhutywa perpendiculars, ngelo xesha kukho omabini amacala xande onesiphumo. A hypotenuse - eli cala idayimani.

Irhombus idibanisa isikweri unxantathu kunye trapezoid QYR QYEW. Le uxande ngenxa nto ndiyibhalayo unxantathu efanayo kunye trapezoid QYEW Wet, ogama ndawo ilingana kummandla kanxantathu QYR. Ngoko ke sigqibo icebisa ngokwalo: QWER irhombus ixabiso ndawo ingqinelana ukuya kummandla QWYT yoxande.

Ngoku ke kucacile ukufumana indlela kummandla irhombus esecaleni ukuphakama kwalo; kufuneka phinda.

Ungafumana kummandla irhombus, yiRHOMBUS ukwazi engile kunye nolwalathiso. Kuyimfuneko kuphela ukuba wazi ukuba yintoni na i sine ye ekujikeni, uze uphinda-phinde ngo kabini ecaleni. Fumana i sine Ungasebenzisa wokubala okanye kwetafile Bradis.

Ngamanye amaxesha, undikhankanye yokufumana ngendlela ummandla irhombus, esebenzisa sine ye-engile kwirediyasi kwisangqa abhaliwe kuyo, apho ngokuyimfuneko kuyachuma.

Noko ke, amaxesha amaninzi ukubala kummandla irhombus nge kwikonw ngekona. Ukusuka kule formula kulandela ukuba le ndawo idayagonali poluproizvedeniyu.

Bonisa ukuba lilula kakhulu, ucinga oonxantathu ezimbini QWE kunye ERQ, ezafumana ngexesha diamond kwenye oxwesileyo. Ezi oonxantathu ayalingana macala ezintathu okanye ezantsi kunye neekona ezimbini ezikufutshane.

Emva kokuchitha nedayimani yesibini oxwesileyo, sinokuyifumana ukuphakama ezi nxantathu, kuba idayagonali phambana ngaxa X kwi-engile degrees 90. Ummandla lo nxantathu QWE imveliso ye-QE, nto leyo intshi omnye wx - isiqingatha sesibini kwikonw ngekona lahlulwe ezimbini.

Ngoku umbuzo yokufumana indlela kummandla irhombus, impendulo icacile: kufuneka kabini eli binzana. Ukuze kube lula ukuzisa ibinzana aljibra abe mnye nemigca luchazwa ngegama le z ileta, ngoxa yesibini - elinonobumba u. sifumana:

2 (z X 1 / 2u: 2) = z X 1 / 2u, ukuba nje ishiya - idayagonali poluproizvedenie.